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有重位点阵关系两相的复合点阵(Ⅱ)——两相空间点阵及其点阵平面的重合系数

杨奇斌

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有重位点阵关系两相的复合点阵(Ⅱ)——两相空间点阵及其点阵平面的重合系数

杨奇斌

COMPOSITE LATTICE OF TWO PHASES WITH A COINCI-DENCE SITE LATTICE RELATIONSHIP (Ⅱ)——COINCIDENCE COEFFICIENTS OF SPACE LATTICES AND PLANE LATTICES

YANG QI-BING
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  • 本文用数论分析方法,给出有重位点阵关系两相空间点阵及其点阵平面重合系数求法的普遍而简便的公式。空间点阵的重合系数α2(3)=1/|C(1)|,点阵平面的重合系数α2(h)= (H(2)C(1)/|C(1)|, C(1)为重位点阵基矢对应矩阵,H(2)=[h1(2)h2(2)h3(2)].在C(1)未知的情况下,空间点阵及其点阵平面的重合系数可以通过两相基矢有理对应矩阵φ及重合系数矩阵C来求,这时α2(3)= k1(2)k2(2)/d3, α2(h)=(CH(2),dk1(2))/d2.求矩阵C比求矩阵C(1)要方便得多。
    Universal and straight-forward formulas for finding coincidence coefficients of space lattices of two phases and their plane lattices having a coincidence site lattice relationship are derived by means of elementary theory of numbers. The coincidence coefficient of a space lattice is α2(3)=1/|C(1)| and that of their plane lattices are α2(h)= (H(2)C(1)/|C(1)|, C(1) being a basic vector correspondence matrix of CSL, and H(2)= [h1(2)h2(2)h3(2)]. In case C(1) is unknown, coincidence coefficients of a space lattice and their plane lattices can be found through the basic vector correspondence matrix φ of two phases and coincidence coefficient matrix C then α23= k1(2)k2(2)/d3, α2(h)=(CH(2),dk1(2))/d2. To find matrix C is much easier than to find C(1).
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出版历程
  • 收稿日期:  1979-10-05
  • 刊出日期:  1980-06-05

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